An urn contains 10 red and 8 white balls. One ball is drawn at random. Find the probability that the ball drawn is white.

Total no of possible outcomes = 18 {10 red balls, 8 white balls}

E ⟶ event of drawing white ball

No. of favourable outcomes = 8 {8 white balls}

Probability, P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes)

= 8/18 = 4/9

Given: A bag contains 10 red and 8 white balls

Required to find: Probability that one ball is drawn at random and getting a white ball

Total number of balls 10 + 8 = 18

Total number of white balls is 8

We know that, Probability = Number of favourable outcomes/ Total number of outcomes

Thus, the probability of drawing a white ball from the urn is 8/18 = 4/9

Total number of red balls = 10

Total number of red white balls = 8

Total number of balls = 10 + 8 = 18

Probability of getting a white ball is = Total number of white balls/Total numbers of balls

= 8/18

= 4/9

∴ Probability of a white ball is 4/9

Total numbers of red balls = 10

Number of red white balls = 8

Total number of balls = 10 + 8 = 18

Probability of getting a white is = \(\frac{Total\,number\,of\,white\,balls}{Total\,number\,of\,balls}\) = \(\frac{8}{18}=\frac{4}{9}\)

Total number of possible outcomes, n(S) = 10 + 8 = 18 

Number of events of getting white ball, N(E) = 8 

Probability,

P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{8}{18}\) = \(\frac{4}{9}\)