The length of a metal wire is l_1 when the tension in it is T_1 and is l_2 when the tension is T, The natural length of the wire is
The length of a metal wire is l1 when the tension in it is T1 and is l2 when the tension is T, The natural length of the wire is
(a) (l1+l2)/2
(b) √(l1l2)
(c) (l1T2-l2 T1)/(T2-T1)
(d) (l1T2+l2T1)/(T2+T1)
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(c) (l1T2-l2 T1)/(T2-T1)
Explanation:
If the original length of the wire be l and the area of the cross-section a, then
l₁-l = T₁*l/Ya
And l₂-l = T₂*l/Ya
Dividing we get,
(l₁ -l)*T₂ = (l₂-l)*T₁
→l₁T₂ -lT₂= l₂ T₁-T₁l
→l(T₂-T₁) = l₁T₂-l₂T₁
→l = (l₁T₂-l₂T₁)/(T₂-T₁)
Hence the option (c).
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