(iii) h(x) = sin2x + 5
We know that − 1 ≤ sin 2x ≤ 1.
∴ − 1 + 5 ≤ sin 2x + 5 ≤ 1 + 5
∴ 4 ≤ sin 2x + 5 ≤ 6
Hence, the maximum and minimum values of h are 6 and 4 respectively.
Solution:
(i) It is not true, in general. This relation is true for some particular values of A and B.
For example, if A = 0 and B = 90,
Then, Sin (A+B)...
f(x)=sin 2x+5
We know that,
-1≤sinӨ≤1
-1≤sin2x≤1
Adding 5 on both sides,
-1+5≤sin2x+5≤1+5
4≤sin2x+5≤6
Hence
Max value of f(x)=sin2x+5 will be 6
Min value of f(x) =sin2x+5 will be 4