Find maximum and minimum value of sin2x+5 from second derivative test.

Question

Find maximum and minimum value of sin2x+5 from second derivative test.

Monjur Alahi

4 views

2025-01-04 04:42

2 Answers

Salim Ahmed Kawsar

f(x)=sin 2x+5

We know that,

-1≤sinӨ≤1

-1≤sin2x≤1

Adding 5 on both sides,

-1+5≤sin2x+5≤1+5

4≤sin2x+5≤6

Hence

Max value of f(x)=sin2x+5 will be 6

Min value of f(x) =sin2x+5 will be 4

4 views Answered 2023-02-05 15:29

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Sir, I'm not getting your answer of my own question.

4 views Answered 2023-02-05 15:29