Find maximum and minimum value of sin2x+5 from second derivative test
Find maximum and minimum value of sin2x+5 from second derivative test
5 views
1 Answers
f(x)=sin 2x+5
We know that,
-1≤sinӨ≤1
-1≤sin2x≤1
Adding 5 on both sides,
-1+5≤sin2x+5≤1+5
4≤sin2x+5≤6
Hence
Max value of f(x)=sin2x+5 will be 6
Min value of f(x) =sin2x+5 will be 4
5 views
Answered