For the equilibrium, 2NOCl(g) ⇌ 2NO(g) + Cl2(g) the value of the equilibrium constant, Kc is 3.75×10–6 at 1069 K
For the equilibrium, 2NOCl(g) ⇌ 2NO(g) + Cl2(g) the value of the equilibrium constant, Kc is 3.75×10–6 at 1069 K. Calculate the Kp for the reaction at this temperature?
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We know that, Kp = Kc (RT)Δn
For the above reaction,
Δn = (2+1) – 2 = 1
Using, Kp = Kc (RT)Δn
Kp = 3.75 ×10–6 (0.0831 × 1069)
Kp = 0.033.
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