Eo values of MnO4-, Ce4+ and Cl2 are 1.507, 1.61 and 1.358 V respectively. Arrange these in order of increasing strength as oxidizing agent.
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How much coulumb is required to convert MnO4^- into Mn^+2
Please recheck your question
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How much coulumb is required to convert MnO4^- into Mn^+2
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Number of moles of MnO4- required to oxidise one mole of ferrous oxalate completely in acidic medium will be:-
Here is Reaction with Balance 10FeC2O4 + 6KMnO4 + 24H2SO4 ----> 3K2SO4+ 6MnSO4 + 5Fe2(SO4)3 + 24H2O + 20CO2 So we see that 6 moles of KMnO4 is required to oxidize 10 moles of FeC2O4 Then, 1 mole of FeC2O4 would be...
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For the reaction, 2Cl(g) → Cl2(g), what are the signs of ∆H and ∆S ?
∆H and ∆S are negative The given reaction represents the formation of chlorine molecule from chlorine atoms. Here, bond formation is taking place. Therefore, energy is being released. Hence, ∆H is negative. Also,...
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Write the balanced redox reaction: a) MnO4 – (aq) + Fe2+ (aq) → Mn2+ (aq) + Fe3+ (aq)
(a) MnO4 – (aq) + 5Fe2+ (aq) + 8H+ (aq) → Mn2+ (aq) + 5Fe3+ (aq) + 4H2O(l) (b) Cr2O72– + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe3+ + 7H2O.
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Identify the oxidizing and reducing agents in the following equations: a) MnO4 – (aq) + 5Fe2+ (aq) + 8H+ (aq) →
Oxidizing agent = MnO4 – and Reducing agent = Fe2+ Oxidizing agent = Cr2O7 2– and Reducing agent = Fe2+ .
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Compare the oxidizing powers of F2 and Cl2 on the basis of bond dissociation enthalpy
[Hint : It is due to low enthalpy of dissociation of F - F bond and high hydration enthalpy of F-.]
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Why is Ce4+ in aqueous solution a good oxidizing agent ?
Because Ce4+ is most stable in Ce+3 state in aqueous solution.
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Why KMnO4 or MnO4 - ion is coloured ?
Due to charge transfer complex formation.
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Balance the following equations : (a) MnO4- + Fe2+ + H+ →
(a) MnO4 - + Fe2+ + H+ → Mn+2 + Fe+3 (b) Cr2O7 2- + Sn2+ + H+→ Cr+3 + Sn+4
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