Answered Feb 05, 2023
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We can clearly see that oxidation number of Mn is 7 in MnO4^- and 2 in Mn^2+ . So the change occured=7-2 =5 Hence number of coulumbs required = 5 x 1faraday = 5 x 96,500 Hence 96,500 x 5 coulumbs are required.
(a) split-ring type commutator must be used
Here is Reaction with Balance 10FeC2O4 + 6KMnO4 + 24H2SO4 ----> 3K2SO4+ 6MnSO4 + 5Fe2(SO4)3 + 24H2O + 20CO2 So we see that 6 moles of KMnO4 is required to oxidize 10 moles of FeC2O4 Then, 1 mole of FeC2O4 would be...
(a) MnO4 – (aq) + 5Fe2+ (aq) + 8H+ (aq) → Mn2+ (aq) + 5Fe3+ (aq) + 4H2O(l) (b) Cr2O72– + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe3+ + 7H2O.
Oxidizing agent = MnO4 – and Reducing agent = Fe2+ Oxidizing agent = Cr2O7 2– and Reducing agent = Fe2+ .
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Cl2 < MnO4 _ < Ce4+
Due to charge transfer complex formation.
(a) MnO4 - + Fe2+ + H+ → Mn+2 + Fe+3 (b) Cr2O7 2- + Sn2+ + H+→ Cr+3 + Sn+4
(a) Solar energy into heal: Solar cooker. (b) Solar energy into electricity: Solar cell.
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