Two books of mass 1 kg each are kept on a table one over the other. The coefficient of friction on every pair of containing surfaces is 0.3. The lower book is pulled with a horizontal force F. The minimum value of F for which slip occurs between the two books is.?

Zero
1.06 N
5.74 N
8.83 N

LohaHridoy

23 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 4 : 8.83 N

Concept:

Friction: The property of a surface that opposes the relative motion between two surfaces is called friction.

m₁ = m₂ = 1 kg; μ = 0.3;

Let N₁ = Reaction between the 1^st book and the 2^nd book.

N₁ = mg = 1 × g = g

N₂ = Reaction between the second book and the ground.

N₂ = 2mg = 2 × 1 × g = 2g

Static friction force

f = μ N₁ + μ N₂

f = μg + 2μg

f = 3μg

For the motion to occur between the books, external force F must be greater than the static friction force

F > f

F > 3μg

F > 3 × 0.3 × 9.81

F > 8.829

F = 8.83 N

23 views Answered 2022-09-04 04:29

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