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Option 4 : 5 mm
The displacement y at x = 30.0 cm and time t = 20 s is given by
y = (0.005 m) sin (80.0 × 0.3 - 3.0 × 20) = (0.005 m) sin (-36)
As sin (2nπ + θ) = sin θ and 12π > 36
= (0.005 m) sin (-36 + 12π)
= (0.005 m) sin (1.699)
As 1 radian = 180°/π ⇒ 1.699 rad = 1.699 × 180°/π = 97°
(It can be approximated as : sin90° ≈ 1)
= (0.005 m) sin (970) ≈ 5 mm
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