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Option 4 : 5 mm

The displacement y at x = 30.0 cm and time t = 20 s is given by

y = (0.005 m) sin (80.0 × 0.3 - 3.0 × 20) = (0.005 m) sin (-36)

As sin (2nπ + θ) = sin θ and 12π > 36

= (0.005 m) sin (-36 + 12π)

= (0.005 m) sin (1.699)

As 1 radian = 180°/π ⇒ 1.699 rad = 1.699 × 180°/π = 97°

(It can be approximated as : sin90° ≈ 1)

= (0.005 m) sin (970) ≈ 5 mm

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