Three numbers which are co-prime to one another are such that the product of the first two is 713 and that of the last two is 1147. The sum of the three numbers is?

75
81
91
100

LohaHridoy

4 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 3 : 91

Given:

Three numbers which are co-prime to one another are such that the product of the first two is 713 and that of the last two is 1147.

Concept:

(LCM × HCF) = Product of the numbers

Calculation:

Since the three numbers are co-prime, they have no common factors other than 1. Therefore, the second would be the only factor in the two products which can be found by H.C.F of the two numbers.

H.C.F (713, 1147) = 31

First Number = 713/31 = 23

Third Number = 1147/31 = 37

Sum of Numbers = 23 + 31 + 37 = 91

∴ The sum of the three numbers is 91.

4 views Answered 2022-09-04 04:29

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