From a point P which is at a distance of 10 cm from the centre O of a circle of radius 6 cm, a pair of tangents PQ and PR to the circle at point Q and R, respectively, are drawn. The area of the quadrilateral PQOR is equal to?

30 sq.cm
40 sq.cm
24 sq.cm
48 sq.cm

LohaHridoy

4 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 4 : 48 sq.cm

Give, OQ = OR = r = 6 cm

OP = 10 cm

In △OQP

(OP)² = (OQ)² + (QP)²

⇒ 10² = 6² + (QP)²

⇒ (QP)²= 100 – 36 = 64

⇒ QP = √64 = 8

Area of △OPQ = 1/2 × Base × Height = (1/2) × 6 × 8 = 24 cm

Area of quadrilateral PQOR = 2 × Area of △OPQ = 2 × 24 = 48 cm

4 views Answered 2022-09-04 04:29

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