A man does double the work done by a boy in the same time. The number of days that 3 men and 4 boys will take to finish a work which can be done by 10 men in 8 days is:?

4
16
\(7\frac{3}{{11}}\)
\(8\frac{4}{5}\)

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 2 : 16

Let efficiency of 1 man and 1 boy be m and b respectively.

m = 2b

m : b = 2 : 1

Work done by 10 men in 8 days = 2 × 10 × 8 = 160

Total efficiency of 3 men and 4 boys = 3 × 2 + 4 × 1 = 10

Required days = 160/10 = 16 days

5 views Answered 2022-09-04 04:29

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