In a projectile motion, the first object is thrown vertically upward with an initial velocity of 40 m/s. After two seconds, a second object is thrown upward with the same velocity. What is the height were they meet?

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In a projectile motion, the first object is thrown vertically upward with an initial velocity of 40 m/s. After two seconds, a second object is thrown upward with the same velocity. What is the height were they meet?

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Dr. Md Rushad Rahman · Answer 1 · Nov 19, 2019 07:12:42

The height would be 76.644 meters. Draw a graph of both objects on the same axis showing the height of object against time. You will see 2 parabolas that intersect at one point. You are asked to find the height of that point. You can do so if you equate the equations of each parabola. The equations would be based on s = ut + (at^2)/2 where s is the height, u is the initial velocity, t is the time elapsed and a is the acceleration due to gravity. The first parabola would be s = 40t + (9.81t^2)/2, and the second parabola would be s = 40(t - 2) + (9.81(t - 2)^2)/2.

In a projectile motion, the first object is thrown vertically upward with an initial velocity of 40 m/s. After two seconds, a second object is thrown upward with the same velocity. What is the height were they meet?

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