1 Answers
Option 4 : 37.5 days
Given:
P can complete 1/5 of the work in 5 days
Q can complete 1/6 of the same work in 5 days
with the help of R they can complete half of the work in 5 days
Concept used:
If the work is constant, then
Time taken ∝ 1/ Efficiency.
Calculation:
Let the total work be 1
P takes 5 days to complete 1/5 work
Total work will be completed in 25 days
A work 1/25 in 1 day
Q takes 5 days to complete 1/6 work
Total work will be completed in 30 days
Q work 1/30 in 1 day
P and Q one day work = 1/25 + 1/30
⇒ P + Q = (6 + 5)/150
⇒ P + Q = 11/150
P and Q completed half of the work
⇒ (11/150) × 2 = 11/75
Half of the work is completed in 5 days by P, Q and R and efficiency is 1/5⇒ P + Q + R - (P + Q) = (1/5) - (11/75)
⇒ Q = (15 - 11)/75 = 4/75
Q takes 75/4 days to complete the half of the work, total work will be completed in
⇒ (75/4) × 2
⇒ 150/4 = 37.5 days
∴ R will take 37.5 days to complete the same work.
Alternate Method
Formula used:
Work = Time × Efficiency
P complete whole work in 25 days
Q complete whole work in 30 days
|
|
Time |
Total work (LCM of time) |
Efficiency |
|
P |
25 |
|
6 |
|
|
|
150 |
|
|
Q |
30 |
|
5 |
P, Q and R complete the half work in 5 days
Efficiency = 75/5 = 15
R efficiency is 15 - 11 = 4
Time taken by R to complete the total work alone is
⇒ 150/4 = 37.5 days
∴ R will take 37.5 days to complete the same work.