If the whole circle bearing of side AB of an equilateral triangle ABC is 38°45’, then the bearing of the third side CA of the triangle is?

278°45’
197°30’
98°45’
81°15’

LohaHridoy

24 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 1 : 278°45’

Calculation:

Given triangle is equilateral triangle so ∠A = ∠B = ∠C = 60°

Given, Bearing of AB = 38°45’

So from traverse diagram, θ = 90° - 38°45’ = 51°15’

And, ϕ = 60° - 51°15’ = 8°45’

So, bearing of third side CA = 270° + 8°45’ = 278°45’

24 views Answered 2022-09-04 04:29

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