1 Answers

Option 1 : 10 days

Given:

Time taken by P to complete the work = 14 days

Time taken by Q to complete the work = 21 days

Q left work after = 6 days

Formula used:

If P and Q can do a piece of work in x and y days, respectively. They start working together and after t days Q leaves the work, then

Time taken to finish whole work = (x/y) × (y - t)

Calculation:

Here, P = 14 days, Q = 21 days, t = 6 days

According to the formula

Time taken to finish whole work = (x/y) × (y - t)

⇒ (14/21) × (21 - 6)

⇒ (2/3) × 15

⇒ 10 days

∴ The time taken to complete the work is 10 days.


Total work = 42 (L.C.M)

Efficiency of P = 3

Efficiency of Q = 2

P and Q work together for 6 days = 6 × (3 + 2)

Work completed = 30

Remaining work = 42 - 30 

⇒ 12

Remaining work completed by P alone = 12/3

⇒ 4 days

Total time = 6 days + 4 days 

⇒ 10 days

∴ The time taken to complete the work is 10 days.

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