1. $$\frac{{1}}{{2}}$$
  2. $$\frac{{2}}{{3}}$$
  3. $$\frac{{3}}{{2}}$$
  4. $$\frac{{3}}{{4}}$$

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Answer: Option 4

Total 4 cases = [HH, TT, TH, HT] Favourable cases = [HH, TH, HT] Please note we need atmost one tail, not atleast one tail. So probability = $$\frac{{3}}{{4}}$$

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