- $$\frac{{3}}{{4}}$$
- $$\frac{{1}}{{4}}$$
- $$\frac{{3}}{{8}}$$
- $$\frac{{7}}{{8}}$$
Answer: Option 4
Getting at most Two heads means 0 to 2 but not more than 2 Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH} Let E = event of getting at most two heads Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT} $$\therefore P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} = \frac{7}{8}$$