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Answer: Option 1
Let P(T) be the probability of getting least one tail when the coin is tossed five times. $$P\left( {\overline T } \right)$$ = There is not even a single tail. i.e. all the outcomes are heads. $$\eqalign{ & P\left( {\overline T } \right) = \frac{1}{{32}} \cr & P\left( T \right) = 1 - \frac{1}{{32}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{31}}{{32}} \cr} $$
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