2 Answers
x3 - 3xy2 + 2y3 = x3 - xy2 - 2xy2 + 2y3 = x (x2-y2) - 2y2 (x-y) = x (x+y) (x-y) - 2y2 (x-y) = (x-y) {x(x+y) - 2y2} (ans:)
3447 views
Answered
x3 - 3xy2 + 2y3 = x3 - xy2 - 2xy2 + 2y3 = x (x2-y2) - 2y2 (x-y) = x (x+y) (x-y) - 2y2 (x-y) = (x-y) {x(x+y) - 2y2} (ans:)
