1 নং প্রশ্নের সমাধান:
= a(a2-b2) b(c2-a2) c(a2-b2)
= a(a2-b2) + bc2 - a2b + ca2 - b2c
= (a-b) {a(a-b) + bc2 - a2b + ca2 - b2c}
= (a-b) {a2 - ab + bc2 - a2b + ca2 - b2c}
= (a-b) {a2 - ab - bc(b-c) - a2(b-c)}
= (a-b) (b-c) {a2 + ab - bc - a2}
= (a-b) (b-c) -b(c-a)
= -b(a-b) (b-c) (c-a) (answer)
2 নং প্রশ্নের সমাধান:
= a2(b-c) b2(c-a) c2(a-b)
=a2(b-c) +b2c -ab2 + c2a - c2b
= a2(b-c) - a(b2-c2) + bc(b-c)
= (b-c) {a2 - a(b-c) + bc}
= (b-c) {a2 - ab + ca + bc}
= (b-c) {-a(c-a) + b(c-a)}
= (b-c) (c-a) (-a+b)
= (b-c) (c-a) -(a-b)
= -(a-b) (b-c) (c-a) (answer)
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