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Gopi and Kishan travel from A to B and the ratio of their speed is 3 ∶ 5. Gopi starts at 10:00 A.M. and Kishan starts at 2:00 P.M. then, find at what time Kishan will overtake Gopi.

Gopi and Kishan travel from A to B and the ratio of their speed is 3 ∶ 5. Gopi starts at 10:00 A.M. and Kishan starts at 2:00 P.M. then, find at what time Kishan will overtake Gopi. Correct Answer 8:00 P.M.

Given:

The ratio of Gopi’s and Kishan’s speed = 3 ∶ 5

Gopi starts at 10:00 A.M.

Kishan starts at 2:00 P.M.

Concept used:

Relative speed is defined as the speed of a moving object with respect to another.

Relative speed = S1 – S2      ...(S1, S2 are speed) (S1 > S2)

Formula used:

Speed = Distance / time

Time to overtake = Distance / Relative speed

Calculations:

Let the speed of Gopi be 3x

Let the speed of Kishan be 5x

⇒ Distance traveled by Gopi before Kishan starts = 3x × 4 = 12x

Relative speed of Gopi and Kishan = 5x – 3x = 2x

Time to overtake = 12x / 2x = 6 hours

Time to overtake = 2:00 P.M. + 6 hours = 8:00 P.M.

∴ Kishan overtakes Gopi at 8:00 P.M.

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