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In a tournament, the number of balls batsman K faced was 84 less than the number of runs faced together by L and M. The average number of balls faced by all three of them was 15 less than that faced by L alone. What is the average number of balls faced by K and L if M faced 5 balls less than K?

In a tournament, the number of balls batsman K faced was 84 less than the number of runs faced together by L and M. The average number of balls faced by all three of them was 15 less than that faced by L alone. What is the average number of balls faced by K and L if M faced 5 balls less than K? Correct Answer 79

Given:

balls M faced less than K = 5

The number of balls batsman K faced = 84 less than the number of runs faced together by L and M.

The average number of balls faced by all three of them = 15 less than that faced by L

Formula:

Average of n numbers a1, a2, ..., an = (a1 + a2 + ... + an) / n

Calculation:

Let the number of balls faced by M be x.

K faced x + 5 balls.

K = L + M - 84

X + 5 = L + x - 84

L = 89

Average = (x + x + 5 + 89) / 3 = 74

2x + 94 = 222

2X = 128

X = 64

The average number of balls faced by K and L = (64 + 5 + 89) / 2 = 158 / 2 = 79

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