If circles x2 + y2 + 8x - 14y + p = 0 and x2 + y2 + 12x + 6y + q = 0 are orthogonal to each other, then what will be the value of 5p + 5q?
If circles x2 + y2 + 8x - 14y + p = 0 and x2 + y2 + 12x + 6y + q = 0 are orthogonal to each other, then what will be the value of 5p + 5q? Correct Answer 30
Calculation:
Condition of orthogonality = 2g1g2 + 2f1f2 = c1 + c2
Calculations:
Given: circles are x2 + y2 + 8x - 14y + p = 0 and x2 + y2 + 12x + 6y + q = 0
So g1 = 4, g2 = 6, f1 = - 7, f2 = 3, c1 = p, c2 = q
2g1g2 + 2f1f2 = c1 + c2 = 2. (4). (6) + 2. ( - 7). (3) = 6
So c1 + c2 = p + q = 6
So 5p + 5q = 5(p + q) = 5×6 = 30
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Feb 20, 2025