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Four equal circles are drawn on the four sides of a square in such a way that each of the circles touches two other circles. What will be the area outside the perimeter of the circles towards the middle of the square? If the measure of each side of the square is 28 cm. 

Four equal circles are drawn on the four sides of a square in such a way that each of the circles touches two other circles. What will be the area outside the perimeter of the circles towards the middle of the square? If the measure of each side of the square is 28 cm.  Correct Answer 168 cm<sup>2</sup>

Given:

Side of the square = 28 cm

Formula used:

Area of square = (side)2

Area of circle = πr2

Calculation:

Four side of the circle inside the square form a circle of radius = 14 cm

According to the question

Area outside the perimeter = (Area of square) – (Area of circle)

⇒ (28)2 – (22/7 × 14 × 14)

⇒ 784 – 616 cm2

⇒ 168 cm2

∴ The required area is 168 cm2

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