An alloy of nickel and tin has 20 % nickel. Another alloy of nickel and copper has nickel and copper in the ratio 1 ∶ 5. Both the alloys are mixed in the ratio 2 ∶ 5. Quantity of tin is what percent more/less than the quantity of nickel in the final alloy?

An alloy of nickel and tin has 20 % nickel. Another alloy of nickel and copper has nickel and copper in the ratio 1 ∶ 5. Both the alloys are mixed in the ratio 2 ∶ 5. Quantity of tin is what percent more/less than the quantity of nickel in the final alloy? Correct Answer 29.72%

Given:

20 % nickel in alloy I

Ratio of nickel and copper = 1 ∶ 5

Calculation:

Nickel = 20 %

Tin = 80 %

⇒ Ratio of nickel and tin = 1 ∶ 4

⇒ Ratio of nickel and copper = 1 ∶ 5

⇒ Ratio in final mixture = 2 ∶ 5

So, total amount of nickel = (1/5) × 2x + (1/6) × 5x

⇒ (2x/5) + (5x/6)

⇒ 37x/30

Total amount of tin = (4/5) × 2x

⇒ 8x/5

Required percentage = {/(37x/30)} × 100