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A container has a mixture of kerosene and water in the ratio of 5 : 7, and another container also has a mixture of water and kerosene in the ratio of 5 : 8. If 12 litres and 13 litres is taken out from first and second container respectively, then what will be the ratio of kerosene and water in the resultant mixture?

A container has a mixture of kerosene and water in the ratio of 5 : 7, and another container also has a mixture of water and kerosene in the ratio of 5 : 8. If 12 litres and 13 litres is taken out from first and second container respectively, then what will be the ratio of kerosene and water in the resultant mixture? Correct Answer 13 : 12

Given:

The mixture of kerosene and water in the first container = 5 : 7

The mixture of water and kerosene in the second container = 5 : 8

The mixture taken out from the first container = 12 litres

The mixture taken out from the second container = 13 litres

Calculation:

The percentage of kerosene in the first mixture = 5/12 × 100 = (500/12)%

The percentage of kerosene in the second mixture = 8/13 × 100 = (800/13)%

Given that, 12 litres are taken out from the first mixture and 13 litres from the second mixture, then

The percentage of kerosene in the resultant mixture = (12 × 500/12 + 13 × 800/13)/(12 + 13)

⇒ (500 + 800)/25

⇒ 1300/25

⇒ 52%

The percentage of water in the resultant mixture = (100 – 52)

⇒ 48

The ratio of kerosene and water in the resultant mixture = 52 : 48

⇒ 13 : 12

∴ The ratio of kerosene and water in the resultant mixture would be 13 : 12. 

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