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1600ml mixture of milk and water contains 40% water. What quantity of the mixture of milk and water should be replaced with 20% water concentration so that the resultant solution contains 30% water concentrate?

1600ml mixture of milk and water contains 40% water. What quantity of the mixture of milk and water should be replaced with 20% water concentration so that the resultant solution contains 30% water concentrate? Correct Answer 800 ml

CALCULATION:

Water in 1600 ml = 40/100 × 1600 = 640 ml

Let x ml of mixture is replaced.

Quantity of water after replacement = 640 - 0.4x + 0.2x = 640 - 0.2x

Now,

640 - 0.2x/1600 × 100 = 30

640 - 0.2x = 480

x = 800 ml

∴ 800 ml mixture should be replaced

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