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There are two containers contain a mixture of wine, water and alcohol. The first container contains wine, water and alcohol in the ratio of 4 : 3 : 3. The second container contain wine, water and alcohol in the ratio of 1 : 2 : 1. If 1 litre from first and 4 litres from second are mixed into the third container. What fraction of alcohol in third container?

There are two containers contain a mixture of wine, water and alcohol. The first container contains wine, water and alcohol in the ratio of 4 : 3 : 3. The second container contain wine, water and alcohol in the ratio of 1 : 2 : 1. If 1 litre from first and 4 litres from second are mixed into the third container. What fraction of alcohol in third container? Correct Answer 13/50

Given:

The first container contains wine, water and alcohol in the ratio is 4 : 3 : 3.

The second container contain wine, water and alcohol in the ratio of 1 : 2 : 1.

Calculation:

The first container contains wine, water and alcohol in the ratio is 4 : 3 : 3.

According to the question,

The quantity of alcohol in first container in 1 litre = (3/10) × 1 = 0.3 litre = 300 ml

The quantity of alcohol in second container in 4 litre = (1/4) × 4 = 1litre = 1000 ml

The total quantity of third container = 1 + 4 = 5 litres = 5000 ml

The quantity of alcohol in third container = 300 + 1000 = 1300 ml

The fraction of alcohol in third container = 1300/5000 = 13/50

∴ The fraction of alcohol in third container is 13/50.

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