If log6 161 = a, log6 23 = b, what is the value of log7 6 in terms of a and b?
If log6 161 = a, log6 23 = b, what is the value of log7 6 in terms of a and b? Correct Answer 1/(a - b)
Calculation :
Given, a = log6 161 = log6 (23 × 7)
= log6 23 + log6 7
also giiven, b = log6 23
⇒ a = b + log6 7
⇒ a - b = log6 7
⇒ log7 6 = 1/(a - b)
Important Points
In this type of question always try to factorize value inside the log and then use these formulas:
log(p × q) = log(p) + log(q)
log(p/q) = log(p) - log(q)
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Feb 20, 2025