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In ascending order, three consecutive integers are placed in a way that sum of last two integers is 13 more than the first integer. What are three possible integers?

In ascending order, three consecutive integers are placed in a way that sum of last two integers is 13 more than the first integer. What are three possible integers? Correct Answer 10, 11 and 12

Given:

In ascending order, three consecutive integers are placed.

Sum of last two integers is 13 more than the first integer.

Concepts used:

Difference between consecutive integers = 1

Calculation:

Let first consecutive integer be x.

⇒ Second consecutive integer = x + 1

⇒ Third consecutive integer = x + 2

⇒ Sum of last two integers = x + 1 + x + 2 = 2x + 3

Sum of last two integers is 13 more than the first integer.

⇒ 2x + 3 = 13 + x

⇒ 2x – x = 13 – 3

⇒ x = 10

⇒ First integer = x = 10, Second integer = x + 1 = 11, Third integer = x + 2 = 12

∴ Three possible integers are 10, 11 and 12.

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