On successively dividing a number by 5, 7 and 9, remainders are 2, 4 and 6 respectively and the final quotient is 2. What will be the remainder if the order of the divisors is reversed?

On successively dividing a number by 5, 7 and 9, remainders are 2, 4 and 6 respectively and the final quotient is 2. What will be the remainder if the order of the divisors is reversed? Correct Answer 7, 4 and 3

Formula used:

Dividend = Divisor × Quotient + Remainder

Calculation:

According to the question,

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z = 9 × 2 + 6 = 24

y = 7 × 24 + 4 = 172

x = 5 × 172 + 2 = 862

Now, divisors is reversed

862 ÷ 9, quotient = 95, and remainder = 7

95 ÷ 7, quotient = 13, and remainder = 4

13 ÷ 5, quotient = 2, and remainder = 3

∴ The remainder is 7, 4, and 3, if the order of the divisors is reversed.