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A number being successively divided by 5, 7 and 9 leaves remainder 2, 4 and 6 respectively. Find the respective remainders if the order of the divisors is reversed.

A number being successively divided by 5, 7 and 9 leaves remainder 2, 4 and 6 respectively. Find the respective remainders if the order of the divisors is reversed. Correct Answer 7, 4, 3

Let the number be x and corresponding quotients when divided by 5, 7 and 9 be y, z and 1 respectively. z = 9*1 + 6 = 15 y = 7z + 4 = 7*15 + 4 = 109 x = 5y + 2 = 5*109 +2 = 547 Respective remainders when the order of the divisors is reversed are 7, 4 and 3 respectively.

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