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The price of a diamond is directly proportional to the square of its weight. A man broke the diamond accidentally into three pieces in the ratio of 6 : 8 : 11 and thus loses Rs 88,880. What was the original price of the diamond?

The price of a diamond is directly proportional to the square of its weight. A man broke the diamond accidentally into three pieces in the ratio of 6 : 8 : 11 and thus loses Rs 88,880. What was the original price of the diamond? Correct Answer Rs 1,37,500

Given:

Men lose Rs. 88,880 when diamond broke into three parts

Concept:

The price of a diamond ∝ (Weight)2

Calculation:

Let be assume the original weight of the diamond is 25 gram

⇒ The original price of diamond = K × (25)2 = 625K

⇒ The diamond has broken into three-part in the ratio = 6 : 8 : 11

⇒ Therefore the weight of the three-part is 6g, 8g, and 11g respectively

⇒ The price of the broken part is 36K, 64K, and 121K respectively

⇒ According to question

⇒ 625K - (36K + 64K + 121K) = 88880

⇒ 625K - 221K = 88880

⇒ 404K = 88880

⇒ K = 88880/404 = 220

⇒ The original price of the diamond = 625K = 625 × 220 = 137,500

∴ The required result will be 137,500.

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