A solid metallic cuboid of dimensions 12 cm × 9 cm × 16 cm is melted and recast into 216 cubes of the same size. What is the lateral surface area of two such cubes?

A solid metallic cuboid of dimensions 12 cm × 9 cm × 16 cm is melted and recast into 216 cubes of the same size. What is the lateral surface area of two such cubes? Correct Answer 32 cm<sup>2</sup>

Given:

Dimension of cuboid = 12 cm × 9 cm × 16 cm

Number of cubes = 216

Formula Used:

The volume of cuboid = Length × Breadth × Height

The volume of cube = (Side)3

The lateral surface area of cube = 4 × (Side)2

Calculation:     

The volume of cuboid = Length × Breadth × Height   

⇒ The volume of cuboid = 12 cm × 9 cm × 16 cm

⇒ The volume of cuboid = 1728 cm3

The volume of cuboid = 216 × The volume of cube

⇒ 1728 = 216 × (Side)3

⇒ 8 = (Side)3

⇒ Side = 2 cm

The lateral surface area of 2 cubes = 2 × 4 × (Side)2

⇒ The lateral srface area of 2 cubes = 8 × (2)2

⇒ The lateral surface area of 2 cubes = 32 cm2

∴ The lateral surface area of 2 cubes is 32 cm2 

The correct option is 2 i.e. 32 cm2

Related Questions

What is the ratio of the volume of a cuboid to the volume of a cube? Statement I. The ratio of the height, breadth, and length of the cuboid is 1 : 2 : 3 and the total surface area of the cuboid is 352 cm2. Statement II. The total surface area of the cube is given to be 384 cm2. Statement III. The length of the cuboid is 3 times the height of the cuboid and 1.5 times the breadth of the cuboid. The difference between the length and the height of the cuboid is 8 cm.