A solid metallic cuboid of dimensions 12 cm × 54 cm × 72 cm is melted and converted into 8 cubes of the same size. What is the sum of the lateral surface areas (in cm2) of 2 such cubes?

A solid metallic cuboid of dimensions 12 cm × 54 cm × 72 cm is melted and converted into 8 cubes of the same size. What is the sum of the lateral surface areas (in cm2) of 2 such cubes? Correct Answer 2592

Given:

Length of cuboid = 12 cm

Breadth of cuboid = 54 cm

Height of the cuboid = 72 cm

It is converted into 8 cubes of the same size

Formula used:

Volume of the cuboid = lbh

Volume of cube = a3

Lateral surface area of the cube = 4a2

Calculation:

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According to the question

⇒ lbh = 8 × a3

⇒ (12 × 54 × 72) = 8 × a3

⇒ (12 × 54 × 9) = a3

⇒ a3 = 5832

⇒ a = 18 cm

Now,

The sum of the lateral surface area of the two such cubes = (4a2 + 4a2)

⇒ 8a2

⇒ 8 × 18 × 18 cm2

⇒ 2592 cm2

∴ The required sum is 2592 cm2

Related Questions

What is the ratio of the volume of a cuboid to the volume of a cube? Statement I. The ratio of the height, breadth, and length of the cuboid is 1 : 2 : 3 and the total surface area of the cuboid is 352 cm2. Statement II. The total surface area of the cube is given to be 384 cm2. Statement III. The length of the cuboid is 3 times the height of the cuboid and 1.5 times the breadth of the cuboid. The difference between the length and the height of the cuboid is 8 cm.