A rigid-jointed plane frame as shown below

A rigid-jointed plane frame as shown below Correct Answer Will sway to left

Concepts:

To check the direction of sway following concepts is required to be applied.

1. If load and frame both are symmetrical then frame does not sway at all.

2. If frame is symmetrical but loading is not then direction of sway can be decided cutting the frame at centre and check the deflection of cantilever frame formed.  The frame will sway in that direction.

Case 1: When load is LHS of the mid span 

[ alt="F1 Abhishek.M 17-11-21 Savita D1" src="//storage.googleapis.com/tb-img/production/21/11/F1_Abhishek.M_17-11-21_Savita_D1.png" style="width: 434px; height: 150px;">

Case 2

[ alt="F1 Abhishek.M 17-11-21 Savita D2" src="//storage.googleapis.com/tb-img/production/21/11/F1_Abhishek.M_17-11-21_Savita_D2.png" style="width: 323px; height: 180px;">

Case 3

[ alt="F1 Abhishek.M 17-11-21 Savita D3" src="//storage.googleapis.com/tb-img/production/21/11/F1_Abhishek.M_17-11-21_Savita_D3.png" style="width: 315px; height: 134px;">

 

3. When both loading and geometry for frame are unsymmetrical, then it is decided based on relative stiffness i.e. I/L ratio.  The frame will sway towards the side which has lesser I/l.

Calculation:

The given frame is unsymmetrical, so

I/L for Left column < I/L for Right column

So, it will sway towards left.

Related Questions

A rod of length L0 makes an angle θ0 with the Y-axis in its rest frame while the rest frame moves to the right along the X-axis with relativistic speed v with respect to lab frame. If $$\gamma = {\left( {1 - \frac{{{v^2}}}{{{c^2}}}} \right)^{ - \frac{1}{2}}},$$    the angle in the lab frame is