A driver drives 20 km towards east. He then takes a left turn and drives 10 km after which he goes 12 km towards west. Next, he takes a right turn and drives 5 km. How far is he from the starting point?

A driver drives 20 km towards east. He then takes a left turn and drives 10 km after which he goes 12 km towards west. Next, he takes a right turn and drives 5 km. How far is he from the starting point? Correct Answer 17 km

The given information can be depicted in the following diagram:

[ alt="08.02.2018.018" src="//storage.googleapis.com/tb-img/production/18/02/08.02.2018.018.PNG" style="height:203px; width:315px"> 

Here, we can see that distance of B from the initial point is 20 – 12 = 8 km and BE = 10 + 5 = 15 km.

[ alt="08.02.2018.019" src="//storage.googleapis.com/tb-img/production/18/02/08.02.2018.019.PNG" style="height:188px; width:295px">

By Pythagoras Theorem:

= √152 + 82

= √289

Therefore, distance of point E from the initial point is 17 km by Pythagoras’ theorem.

Related Questions

How far is point 'R' from Point 'T'? Statement (I): Point 'R' is 5 metres to the north of point 'M'. Point 'U' is 4 metres to the east of point 'R'. Point 'T' is to the west of point 'R' such that points 'U' 'R' and 'T' form a straight line of  metres. Statement (II): Point 'Z' is metres to the south of point 'T'. Point 'U' is  metres to the east of point 'T'. Point 'M' is  metres to the east of point 'Z'. Point 'R' is  metres to the north of point 'M'. Point 'R' lies on the line formed by joining points 'T' and 'U'.