There are 2 inlet taps and 2 outlet tap in a tank. Inlet taps X and Y can fill the tank in 20 and 24 hours respectively while the two outlet taps P and Q have equal efficiency. If all the taps are opened together then the tank is filled in 40 hours, then find in how many hours tap P alone will empty the 2/3rd of the tank.

There are 2 inlet taps and 2 outlet tap in a tank. Inlet taps X and Y can fill the tank in 20 and 24 hours respectively while the two outlet taps P and Q have equal efficiency. If all the taps are opened together then the tank is filled in 40 hours, then find in how many hours tap P alone will empty the 2/3rd of the tank. Correct Answer 20 hours

Suppose capacity of the tank = 120 units (LCM of 20 and 24)

⇒ Efficiency of tap X = 120/20 = 6

⇒ Efficiency of tap Y = 120/24 = 5

Suppose the efficiency of tap P and Q = x

Since when all the taps are opened together then the tank is filled in 40 hours

⇒ (6 + 5) × 40 – 40 × 2x = 120

⇒ 80x = 320

⇒ x = 4

⇒ Efficiency of tap P and Q = 4

∴ Time taken by tap P to empty 2/3rd tank = (120/4) × 2/3 = 20 hours

Related Questions

The following questions have three statements. Study the question and the statements and decide which of the statement(s) is/are necessary to answer the question. In how many hours tap B can fill the completely empty tank? Statement I: The inlet tap A and the outlet tap C working simultaneously takes 40 hours to fill the tank. Statement II: Efficiency of inlet tap B is equal to efficiency of outlet tap C or 62.5% of the efficiency of inlet tap A. Statement III: The outlet tap C can empty a half filled tank in 12 hours.