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Truck X started from city A and reached city B in 4.5 hours, while another truck Y started from city B and reached city A in 3.6 hours. If both the trucks had started at the same time from their respective cities, after how many would they meet? 

Truck X started from city A and reached city B in 4.5 hours, while another truck Y started from city B and reached city A in 3.6 hours. If both the trucks had started at the same time from their respective cities, after how many would they meet?  Correct Answer 2 hours

Let the distance between the two cities be ‘d’ km

Truck X completed its journey in 4.5 hours,

⇒ Speed of truck X = Distance/Time = d/4.5 = (2d/9) km/hr.

Truck Y completed its journey in 3.6 hours,

⇒ Speed of truck Y = d/3.6 = (5d/18) km/hr.

Now, if the two trucks started at the same time, they are moving towards each other with a relative speed that is equal to the sum of their individual speeds

⇒ Relative speeds of trucks = (2d/9) + (5d/18) = (d/2) km/hr.

∵ Time after which they meet = Distance between cities/Their relative speed

∴ The two trucks will meet after = d/(d/2) = 2 hours

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