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Suresh alone takes 20 days to do a piece of work. Rajesh alone takes 30 days to do the same piece of work. The total wages for the entire work is Rs. 10,000. How much should Suresh be paid if they work together for the entire duration of the work?

Suresh alone takes 20 days to do a piece of work. Rajesh alone takes 30 days to do the same piece of work. The total wages for the entire work is Rs. 10,000. How much should Suresh be paid if they work together for the entire duration of the work? Correct Answer Rs. 6000

Suresh one day work = 1/20

Rajesh one day work = 1/30

Suresh and Rajesh one day work =

⇒ 1/20 + 1/30

⇒ 5/60

⇒ 1/12

Suresh and Rajesh can complete the work in 12 days.

Total work to be done is 60.

Work done by suresh in one day = 60/20 = 3 units.

Work done by Rajesh in one day = 60/30 = 2 units.

Total wages for the entire work = Rs. 10000.

Wage for per unit of work = 10000/3 + 2 = 10000/5 = Rs. 2000.

Wages to be paid to Suresh = 2000 × 3 = Rs. 6000

Alternate method:

Suresh one day work = 1/20

Rajesh one day work = 1/30

So efficiency ratio = 1/20 : 1/30 = 3 : 2

So suresh’ wages = 3/5 × 10,000 = 6,000

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