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The table given presents the Rainfall (in mm) in two cities on different days of a week. Days Rainfall (in mm) City 1 City 2 D1 82 81.6 D2 78 79.4 D3 76.2 78.3 D4 81.6 77.7 D5 79.4 84 D6 84 83 D7 83.8 82   The rainfall on day D2 in City 1 is how much percent more than the rainfall on day D4 in City 2?

The table given presents the Rainfall (in mm) in two cities on different days of a week. Days Rainfall (in mm) City 1 City 2 D1 82 81.6 D2 78 79.4 D3 76.2 78.3 D4 81.6 77.7 D5 79.4 84 D6 84 83 D7 83.8 82   The rainfall on day D2 in City 1 is how much percent more than the rainfall on day D4 in City 2? Correct Answer <span class="math-tex">\(\frac{{100}}{{259}}\)</span>

Given, the rainfall on day D2 in City 1 = 78 mm

And, the rainfall on day D4 in City 2 = 77.7 mm

So, the required percent = (78 – 77.7) × 100/77.7

⇒ 300/777

∴ The required percent = 100/259%

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