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Point K lies between points P and Q such that the length of QK is thrice that of PK. Two cars start traveling towards each other from the endpoints. The car started from Q reaches K one hour after another car which started from P. If the speed of the car started from Q is half of that of another car, then how much time is taken by the first car in reaching K from P?

Point K lies between points P and Q such that the length of QK is thrice that of PK. Two cars start traveling towards each other from the endpoints. The car started from Q reaches K one hour after another car which started from P. If the speed of the car started from Q is half of that of another car, then how much time is taken by the first car in reaching K from P? Correct Answer 12 Min

Let the distance between PK be x, and Speed of the first car be S

⇒ Distance between QK = 3x

⇒ Speed of the second car = 2S

Let the first car takes ‘t’ hr to reach K

⇒ Time taken by second car to reach K = (t + 1) hr

We know that

⇒ Speed = Distance/Time

Time taken by car from P to K, t = x/S

Time taken by car from Q to K = 3x/(S/2) = 6x/S = 6t

According to the question,

6t = t + 1

⇒ 5t = 1

⇒ t = 12 min

∴ Time taken by the first car to reach K 3 will be 12 Min

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