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A clipper circuit is shown below: Assuming forward voltage drops of the diodes to be 0.7 V, the input-output transfer characteristics for the circuit will be

A clipper circuit is shown below: Assuming forward voltage drops of the diodes to be 0.7 V, the input-output transfer characteristics for the circuit will be Correct Answer <img alt="F2 S.B Madhu 03.06.20 D4" src="//storage.googleapis.com/tb-img/production/20/06/F2_S.B_Madhu_03.06.20_D4.png" style="width: 249px; height: 152px;">

Concept:

For normal diode:

If Vp > Vn; diode is ON

If Vp < Vn; Diode is OFF

Where Vp and Vn are the voltages applied at the p-side and n-side respectively.

For Zener diode:

If |Vpn| > Vz ; Zener diode is ON

If |Vpn| < Vz ; Zener diode is OFF

Application:

Case I: Vi < – 0.7 V

For Vi < -0.7 V, the PN diode will be OFF and the Zener diode will be forward bias, behaving like a normal diode.

The equivalent circuit is drawn as:

[ alt="F2 S.B Madhu 03.06.20 D6" src="//storage.googleapis.com/tb-img/production/20/06/F2_S.B_Madhu_03.06.20_D6.png" style="width: 269px; height: 108px;">

∴ The output voltage V0 will be:

V0 + 0.7 = 0

V0 = - 0.7 V

Case II: -0.7 ≤ Vi ≤ 5.7

The circuit is drawn as:

[ alt="F2 S.B Madhu 03.06.20 D7" src="//storage.googleapis.com/tb-img/production/20/06/F2_S.B_Madhu_03.06.20_D7.png" style="width: 220px; height: 108px;">

The output voltage will be:

V0 = Vi

Case III: 5.7 < Vi < 10

For this range, Diode D will be ON and the Zener will be OFF. The equivalent circuit is as shown:

[ alt="F2 S.B Madhu 03.06.20 D8" src="//storage.googleapis.com/tb-img/production/20/06/F2_S.B_Madhu_03.06.20_D8.png" style="width: 265px; height: 108px;">

The output voltage is therefore:

V0 – 0.7 – 5 = 0

V0 = 5.7

From the result obtained above, the transfer characteristic will be:

[ src="//storage.googleapis.com/tb-img/production/20/06/F2_S.B_Madhu_03.06.20_D9.png" style="width: 247px; height: 156px;">

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