How much will the height of the cuboid made by melting the cube having diagonal 22√3 cm? If the length of the cuboid is equal to the arm of the cube, and the width of the cuboid is 11 cm. (in cm)

How much will the height of the cuboid made by melting the cube having diagonal 22√3 cm? If the length of the cuboid is equal to the arm of the cube, and the width of the cuboid is 11 cm. (in cm) Correct Answer 44

As we know,

Volume of cube = a3

Volume of cuboid = lbh

Diagonal of the cube = √3a

⇒ √3a = 22 √3

⇒ a = 22 cm

Length of the cuboid, l = 22 cm

Let the height of the cuboid be h cm

Width of the cuboid, b = 11 cm

According to the question

22 × 11 × h = 22 × 22 × 22

⇒ h = (22 × 22 × 22)/(22 × 11)

∴ h = 44 cm

Related Questions

What is the ratio of the volume of a cuboid to the volume of a cube? Statement I. The ratio of the height, breadth, and length of the cuboid is 1 : 2 : 3 and the total surface area of the cuboid is 352 cm2. Statement II. The total surface area of the cube is given to be 384 cm2. Statement III. The length of the cuboid is 3 times the height of the cuboid and 1.5 times the breadth of the cuboid. The difference between the length and the height of the cuboid is 8 cm.