The table below shows the frequency distribution of a certain mass data. Class Interval 0-25 25-50 50-75 75-100 100-125 Frequency 2 7 6 3 8 As a tradition, the lower limit is always included in the class interval (CI); and the upper limit is removed from every CI, except the last. For the given data, x is the upper limit of the model class and y is the lower limit of the median class. Then what is the value of (2x - 5y)?

The table below shows the frequency distribution of a certain mass data. Class Interval 0-25 25-50 50-75 75-100 100-125 Frequency 2 7 6 3 8 As a tradition, the lower limit is always included in the class interval (CI); and the upper limit is removed from every CI, except the last. For the given data, x is the upper limit of the model class and y is the lower limit of the median class. Then what is the value of (2x - 5y)? Correct Answer 0

Class Interval

0-25

25-50

50-75

75-100

100-125

Frequency

2

7

6

3

8

As, the maximum frequency is 8.

Hence, modal class = 100-125.

∴ x = Upper limit of the model class = 125

Class Interval 0-25 25-50 50-75 75-100 100-125
Frequency 2 7 6 3 8
Cumulative Frequency 2 9 15 18 26 = N

N/2 = 26/2 = 13

Cumulative frequency just greater than 13 is 15 and the corresponding class is 50-75.

Hence, median class = 50-75.

∴ y = Lower limit of the median class = 50

Now,

2x - 5y = 2 × 125 - 5 × 50 = 250 - 250 = 0.

Related Questions

What is the formula for the median of Grouped data? * h b) Median = L + * h c) Median = L + + h d) Median = L * * h