The table below shows the frequency distribution of a certain mass data. Class Interval 0-25 25-50 50-75 75-100 100-125 Frequency 2 7 6 3 8 As a tradition, the lower limit is always included in the class interval (CI); and the upper limit is removed from every CI, except the last. For the given data, x is the upper limit of the model class and y is the lower limit of the median class. Then what is the value of (2x - 5y)?
The table below shows the frequency distribution of a certain mass data. Class Interval 0-25 25-50 50-75 75-100 100-125 Frequency 2 7 6 3 8 As a tradition, the lower limit is always included in the class interval (CI); and the upper limit is removed from every CI, except the last. For the given data, x is the upper limit of the model class and y is the lower limit of the median class. Then what is the value of (2x - 5y)? Correct Answer 0
|
Class Interval |
0-25 |
25-50 |
50-75 |
75-100 |
100-125 |
|
Frequency |
2 |
7 |
6 |
3 |
8 |
As, the maximum frequency is 8.
Hence, modal class = 100-125.
∴ x = Upper limit of the model class = 125
| Class Interval | 0-25 | 25-50 | 50-75 | 75-100 | 100-125 |
| Frequency | 2 | 7 | 6 | 3 | 8 |
| Cumulative Frequency | 2 | 9 | 15 | 18 | 26 = N |
N/2 = 26/2 = 13
Cumulative frequency just greater than 13 is 15 and the corresponding class is 50-75.
Hence, median class = 50-75.
∴ y = Lower limit of the median class = 50
Now,
2x - 5y = 2 × 125 - 5 × 50 = 250 - 250 = 0.