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A container is full of water, 36 litres of water is drawn from it and it is then filled with milk, 36 litres of the mixture is again drawn and the container is again filled with milk. If the ratio of water and mil is 36 ∶ 13, then how much liquid does the container hold?

A container is full of water, 36 litres of water is drawn from it and it is then filled with milk, 36 litres of the mixture is again drawn and the container is again filled with milk. If the ratio of water and mil is 36 ∶ 13, then how much liquid does the container hold? Correct Answer 252 litres

Given:

A container is full of water, 36 litres of water is drawn from it and it is then filled with milk, 36 litres of the mixture is again drawn and the container is again filled with milk and the ratio of water and milk is 36 ∶ 13

Concept Used: 

If there is 'a' volume of water initially and in each operation 'b' volume is taken out and replaced by 'b' volume of milk, then at the end of n such operations, the quantity of water in the mixture = {(a - b)/a}n

Calculation:

Let the quantity of water which is full initially in the container be 'x' litres.

after 'n = 2' such operation, we have

⇒ 36/49 = (x - 36)2/x2

⇒ 6/7 = (x - 36)/x

⇒ 6x = 7x - 252

⇒ x = 252 litres

∴ The required quantity of water which is full initially is 252 litres.           

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