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A container has two holes. The 1st hole alone empties the container in 15 minutes and 2nd hole alone empties the container in 10 minutes. If water leaks out at a constant rate, how long (in minutes) does it take if both the holes together empty the container?

A container has two holes. The 1st hole alone empties the container in 15 minutes and 2nd hole alone empties the container in 10 minutes. If water leaks out at a constant rate, how long (in minutes) does it take if both the holes together empty the container? Correct Answer 6

Given:

A container has two holes.

Calculation:

1st hole alone empty the tank in 15min

2nd hole alone empty the tank in 10min

LCM of 15, 10 = 30

Let the total capacity of the tank is 30units

Efficiency of hole1 = 30/15 = 2units/min

Efficiency of hole2 = 30/10 = 3units/min

According to question:

When these both hole work together, time taken to empty the tank

⇒ total efficiency when they both work together = 3+2 = 5units/min

Time taken to empty the tank = 30/5 = 6min

∴ Required time = 6min

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