A tank has two leakages. The first leakage alone can empty the tank in 9 min and the second alone would have done it in 6 min. If water leaks out at a constant rate , how long does it take both the leakage together to empty the tank?
A tank has two leakages. The first leakage alone can empty the tank in 9 min and the second alone would have done it in 6 min. If water leaks out at a constant rate , how long does it take both the leakage together to empty the tank? Correct Answer 3.6 min
1st leakage, in 9 min can empty = 1 part " 1 " " " " = 16" Both the leakage in 1 min together to empty the tank = 19 + 16 Part = 2 + 318" = 518 Part.'. 518 Part can empty = 1min1 " " " " = 15 " = 185 " = 3.6 min